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Next, we eliminate all free variables from φ by quantifying them existentially: if, say, x < sub > 1 </ sub >... x < sub > n </ sub > are free in φ, we form.
If ψ is satisfiable in a structure M, then certainly so is φ and if ψ is refutable, then is provable, and then so is ¬ φ, thus φ is refutable.
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