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Every simple R-module is isomorphic to a quotient R / m where m is a maximal right ideal of R. By the above paragraph, any quotient R / m is a simple module.
Conversely, suppose that M is a simple R-module.
Then, for any non-zero element x of M, the cyclic submodule xR must equal M. Fix such an x.
The statement that xR = M is equivalent to the surjectivity of the homomorphism that sends r to xr.
The kernel of this homomorphism is a right ideal I of R, and a standard theorem states that M is isomorphic to R / I.
By the above paragraph, we find that I is a maximal right ideal.
Therefore M is isomorphic to a quotient of R by a maximal right ideal.

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