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So and P
So any point P =( x, y ) on the parabola will be equidistant both to ( 0, f ) and ( x ,- f ).
P. Schuyler Miller gave the book a favorable review as " a first-rate historical novel of the near future ," saying " So subtly has the scientific detail been interwoven with plot and action that the reader never realizes how painstakingly it has been worked out.
So an eclipse cycle is any period P for which approximately holds:
In each set, incisors ( I ) are indicated first, canines ( C ) second, premolars ( P ) third, and finally molars ( M ), giving I: C: P: M. So for example, the formula 2. 1. 2. 3 for upper teeth indicates 2 incisors, 1 canine, 2 premolars, and 3 molars on one side of the upper mouth.
So 2 is a root of P ’, but not of P.
So if there is such a predicate P and a theorem:
So, the mental event of deciding to pick up a rock (" M ") is caused by the firing of specific neurons in the brain (" P ").
So, let x be any one particular friend of Peter, X the set of all Peter's friends, P ( x ) be the predicate ( mathematical logic ) " x likes to dance ", and lastly Q ( x ) the predicate " x likes to go to the beach ".
Furthermore, the elements that are actually in P are precisely those whose reflection vanishes at P. So if we think of the map, associated to any element a of A:
So the column vectors of P are eigenvectors of A, and the corresponding diagonal entry is the corresponding eigenvalue.
So komal Re / Ri uses the letter r and shuddha Re / Ri, the letter R, but shuddha Ma uses m because it has a raised form-tivra Ma-which uses the letter M. Sa and Pa are always abbreviated as S and P, respectively, since they cannot be altered.
So construct the midpoint H between O and P, and draw a circle centered at H through O and P. By Thales ' theorem, the sought point T is the intersection of this circle with the given circle k, because that is the point on k that completes a right triangle OTP.
* " The Cruise " ( which features Miki Berenyi ) is a reworking of the song " So Soon " ( featuring Petra Haden ), previously released as a b-side for the " Friends Of P " single.
So there exists an invertible matrix P such that P < sup >- 1 </ sup > AP = J is such that the only non-zero entries of J are on the diagonal and the superdiagonal.
* None Are So Blind — Adapted by James P. Cavanagh for Alfred Hitchcock Presents, October 28, 1956 ( Season 2, Episode 5 ), starring Hurd Hatfield and Mildred Dunnock.
Frost fronted a number of programmes following the success of TW3, including its immediate successor, Not So Much a Programme, More a Way of Life, which he co-chaired with Willie Rushton and P. J. Kavanagh.
So I must not only know the proposition P, and the fact that P is the case, but also know that the fact that P is the case is what makes proposition P true.

So and <
So a quasar at an absolute magnitude of − 25. 5 is 100 times brighter than our galaxy ( because ( 10 < sup > 0. 4 </ sup >)< sup >(− 20. 5 -(− 25. 5 ))</ sup >
After Christians in Ephesus first wrote to their counterparts recommending Apollos to them, he went to Achaia where Paul names him as an apostle ( 1 Cor 4: 6, 9-13 ) Given that Paul only saw himself as an apostle ' untimely born ' ( 1 Cor 15: 8 ) it is certain that Apollos became an apostle in the regular way ( as a witness to the risen Lord and commissioned by Jesus-1 Cor 15: 5-9 ; 1 Cor 9: 1 ).< ref > So the Alexandrian recension ; the text in < sup > 38 </ sup > and Codex Bezae indicate that Apollos went to Corinth.
So, for example, while R < sup > n </ sup > is a Banach space with respect to any norm defined on it, it is only a Hilbert space with respect to the Euclidean norm.
So, substituting the angular momentum and moment of inertia into E < sub > rot </ sub >, the rotational energy levels of a diatomic molecule are given by:
So the parameters are: a — distance from center C to either vertex b — length of a perpendicular segment from each vertex to the asymptotes c — distance from center C to either Focus point, F < sub > 1 </ sub > and F < sub > 2 </ sub >, and θ — angle formed by each asymptote with the transverse axis.
So the logarithm function is in fact a group isomorphism from the group ( R < sup >+</ sup >,< big >×</ big >) to the group ( R ,< big >+</ big >).
) So far, observations show any rotation of the Universe is very slow ( no faster than once every 60 · 10 < sup > 12 </ sup > years ( 10 < sup >− 13 </ sup > rad / yr )), and debate persists over whether there is any rotation.
So in the example above, the has simply been replaced by < code >< nowiki > http :// usemod. com / cgi-bin / mb. pl ?</ nowiki ></ code > in creating the target of the HTML rendered link.
So if there are m factors, there will be 2 < sup > m </ sup > idempotents.
So, in these cases, the lethal concentration may be given simply as LC < sub > 50 </ sub > and qualified by a duration of exposure ( e. g., 10 minutes ).
So < sup > 256 </ sup > Fm was produced by the decays of cyclotron-synthesized mendelevium.
So if L ( r ) is proportional to r < sup >− 2 </ sup >, then for to be finite, N ( r ) must be proportional to r < sup > b </ sup >, where b < 1.
So beginning at the left and moving to the right, find the first ( and in this case, the only ) parenthesis, that is, ( 2 + 2 < sup > 2 </ sup >).
So the correct value for our original expression, 4 × 2 < sup > 2 </ sup >( 2 + 2 < sup > 2 </ sup >), is 10.
So, < τέλειος > (< téleios >, meaning " perfect " and " complete ") yields < τέλεια > (< téleia >, " perfectly ") and < τελείως > (< teleíos >, " completely ").
So the output contains sinusoidal terms with frequencies at the sum ω < sub > 1 </ sub > + ω < sub > 2 </ sub > and difference ω < sub > 1 </ sub >-ω < sub > 2 </ sub > of the two original frequencies.

So and sub
So, for example, H ( C = O )( CHOH )< sub > 4 </ sub > H is pentose, H ( CHOH )( C = O )( CHOH )< sub > 3 </ sub > H is pentulose, and H ( CHOH )< sub > 2 </ sub >( C = O )( CHOH )< sub > 2 </ sub > H is pent-3-ulose.

So and n
So there is a short non-halting algorithm whose output converges ( after finite time ) onto the first n bits of Omega.
So, for example, a bifunctor is a multifunctor with n
Kid Rock released Rock n Roll Jesus, which produced hits in " So Hott ", " Amen " and " All Summer Long ".
) So the size of H divides n !.
So, if the TDM frame consists of n voice frames, the bandwidth will be n * 64 kbit / s.
So the value of a GFN increases exponentially, in proportion to 2 < sup > n </ sup >.
So, if n > 0 is an integer and there are integers 1 < a, b < n such that n = a × b, then n is composite.
So if it's not known whether a number n is prime or composite, we can pick a random number a, calculate the Jacobi symbol and compare it with Euler's formula ; if they differ modulo n, then n is composite ; if they're the same modulo n for many different values of a, then n is " probably prime ".
For instance, if we look for the divisors of a number as described above, the number of candidates tested will be the given number n. So if n has sixteen decimal digits, say, the search will require executing at least 10 < sup > 15 </ sup > computer instructions, which will take several days on a typical PC.
So for integer n, A < sup > n </ sup > is symmetric if A is symmetric.
So the various components can be viewed as forming a hierarchy of memories ( m < sub > 1 </ sub >, m < sub > 2 </ sub >,..., m < sub > n </ sub >) in which each member m < sub > i </ sub > is in a sense subordinate to the next highest member m < sub > i-1 </ sub > of the hierarchy.
So the number of particles n intersecting a unit area of grain boundary is:
So, for example, the sum of the terms of the arithmetic progression given by a < sub > n </ sub >

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