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Page "Yoneda lemma" ¶ 25
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Given and morphism
Given a functor F: J C ( thought of as an object in C < sup > J </ sup >), the limit of F, if it exists, is nothing but a terminal morphism from Δ to F. Dually, the colimit of F is an initial morphism from F to Δ.
Given a functor U and an object X as above, there may or may not exist an initial morphism from X to U. If, however, an initial morphism ( A, φ ) does exist then it is essentially unique.
Given a diagram F: J C ( thought of as an object in C < sup > J </ sup >), a natural transformation ψ: Δ ( N ) F ( which is just a morphism in the category C < sup > J </ sup >) is the same thing as a cone from N to F. The components of ψ are the morphisms ψ < sub > X </ sub >: N F ( X ).
* Given any morphism k ′: K ′ X such that f k ′ is the zero morphism, there is a unique morphism u: K ′ K such that k u
Given two reductive groups and a ( well behaved ) morphism between their corresponding L-groups, this conjecture relates their automorphic representations in a way that is compatible with their L-functions.
Given two such associative unital K-algebras A and B, a unital K-algebra morphism f: A B is a ring morphism that commutes with the scalar multiplication defined by η, which one may write as
Given a statement regarding the category C, by interchanging the source and target of each morphism as well as interchanging the order of composing two morphisms, a corresponding dual statement is obtained regarding the opposite category C < sup > op </ sup >.
* Given any manifold, there is a Lie groupoid called the pair groupoid, with as the manifold of objects, and precisely one morphism from any object to any other.
* Given a Lie group acting on a manifold, there is a Lie groupoid called the translation groupoid with one morphism for each triple with.
Given a category C and a morphism
Given any morphism between objects X and Y, if there is an inclusion map into the domain, then one can form the restriction fi of f. In many instances, one can also construct a canonical inclusion into the codomain R Y known as the range of f.
Given and, a morphism in the coslice category is a map making the following diagram commute:
Given two representations ρ: G GL ( n, C ) and τ: G GL ( m, C ) a morphism between ρ and τ is a linear map T: C < sup > n </ sup > C < sup > m </ sup > so that for all g in G we have the following commuting relation: T ° ρ ( g ) = τ ( g ) ° T.
Given a morphism, any vector bundle on Y, or more generally any sheaf in modules, eg.
#( TR 3 ) Given a map between two morphisms, there is a morphism between their mapping cones ( which exist by axiom ( TR 1 )), that makes everything commute.

Given and f
Given any element x of X, there is a function f < sup > x </ sup >, or f ( x ,·), from Y to Z, given by f < sup > x </ sup >( y ) := f ( x, y ).
Given a function f of type, currying it makes a function.
Given a function f ∈ I < sub > x </ sub > ( a smooth function vanishing at x ) we can form the linear functional df < sub > x </ sub > as above.
Given two manifolds M and N, a bijective map f from M to N is called a diffeomorphism if both
Given a subset X of a manifold M and a subset Y of a manifold N, a function f: X Y is said to be smooth if for all p in X there is a neighborhood of p and a smooth function g: U N such that the restrictions agree ( note that g is an extension of f ).
Given two groups G and H and a group homomorphism f: G H, let K be a normal subgroup in G and φ the natural surjective homomorphism G G / K ( where G / K is a quotient group ).
Given a trigonometric series f ( x ) with S as its set of zeros, Cantor had discovered a procedure that produced another trigonometric series that had S ' as its set of zeros, where S ' is the set of limit points of S. If p ( 1 ) is the set of limit points of S, then he could construct a trigonometric series whose zeros are p ( 1 ).
Given f ∈ G ( x * x < sup >- 1 </ sup >, y * y < sup >-1 </ sup >) and g ∈ G ( y * y < sup >-1 </ sup >, z * z < sup >-1 </ sup >), their composite is defined as g * f ∈ G ( x * x < sup >-1 </ sup >, z * z < sup >-1 </ sup >).
Given the laws of exponents, f ( x )
Given a function f of a real variable x and an interval of the real line, the definite integral
Given a function ƒ defined over the reals x, and its derivative ƒ < nowiki > '</ nowiki >, we begin with a first guess x < sub > 0 </ sub > for a root of the function f. Provided the function is reasonably well-behaved a better approximation x < sub > 1 </ sub > is
# Given any point x in X, and any sequence in X converging to x, the composition of f with this sequence converges to f ( x )
Given f
Given metric spaces ( X, d < sub > 1 </ sub >) and ( Y, d < sub > 2 </ sub >), a function f: X Y is called uniformly continuous if for every real number ε > 0 there exists δ > 0 such that for every x, y ∈ X with d < sub > 1 </ sub >( x, y ) < δ, we have that d < sub > 2 </ sub >( f ( x ), f ( y )) < ε.
Given the space X = Spec ( R ) with the Zariski topology, the structure sheaf O < sub > X </ sub > is defined on the D < sub > f </ sub > by setting Γ ( D < sub > f </ sub >, O < sub > X </ sub >) = R < sub > f </ sub >, the localization of R at the multiplicative system

Given and B
: Given any set A and any set B, if for every set C, C is a member of A if and only if C is a member of B, then A is equal to B.
: Given any set A and any set B, if A is a nonempty set ( that is, if there exists a member C of A ), then if A and B have precisely the same members, then they are equal.
: Given any set A and any set B, there is a set C such that, given any set D, D is a member of C if and only if D is equal to A or D is equal to B.
: Given any set A, there is a set B such that, given any set x, x is a member of B if and only if x is a member of A and φ holds for x.
: Given any set A, there is a set such that, given any set B, B is a member of if and only if B is a subset of A.
: Given any set A, there is a set B such that, for any element c, c is a member of B if and only if there is a set D such that c is a member of D and D is a member of A.
Given a circle A, find a circle B such that the area of the intersection of A and B is equal to the area of the symmetric difference of A and B ( the sum of the area of AB and the area of BA ).
Given a core geometry, the B field needed for a given force can be calculated from ( 2 ); if it comes out to much more than 1. 6 T, a larger core must be used.
Given two candidates, A and B, A is better than B on a constraint if A incurs fewer violations than B.
With regard to African Americans, Gilman wrote in the American Journal of Sociology: “ The problem, is this: Given: in the same country, Race A, progressed in social evolution, say, to Status 10 ; and Race B, progressed in social evolution, say, to Status 4..

Given and
* Given any Banach space X, the continuous linear operators A: X X form a unitary associative algebra ( using composition of operators as multiplication ); this is a Banach algebra.
* Given any set X, there is an equivalence relation over the set of all possible functions X X.
Given a class function G: V V, there exists a unique transfinite sequence F: Ord V ( where Ord is the class of all ordinals ) such that
Given a function f: X Y, the set X is the domain of f ; the set Y is the codomain of f. In the expression f ( x ), x is the argument and f ( x ) is the value.
* Given a category C with finite coproducts, a cogroup object is an object G of C together with a " comultiplication " m: G G G, a " coidentity " e: G 0, and a " coinversion " inv: G G, which satisfy the dual versions of the axioms for group objects.
Given a subset S in R < sup > n </ sup >, a vector field is represented by a vector-valued function V: S R < sup > n </ sup > in standard Cartesian coordinates ( x < sub > 1 </ sub >, ..., x < sub > n </ sub >).
Given a vector x ∈ V and y * ∈ W *, then the tensor product y * ⊗ x corresponds to the map A: W V given by
: Given two sets, A and T, of equal size, together with a weight function C: A × T R. Find a bijection f: A T such that the cost function:
Given a concrete category ( C, U ) and a cardinal number N, let U < sup > N </ sup > be the functor C Set determined by U < sup > N </ sup >( c ) = ( U ( c ))< sup > N </ sup >.

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