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Multiplying and th
Multiplying the numbers of each line of Pascal's triangle down to the n < sup > th </ sup > Line by the numbers of the n < sup > th </ sup > Line generates the n < sup > th </ sup > Layer of the Tetrahedron.

Multiplying and number
Multiplying the result by the number of cylinders in the engine gives the engine's total displacement.
Multiplying a vector by a positive number changes its length without changing its direction.
Multiplying 020408163265306122448979591836734693877551 by each of these integers results in a cyclic permutation of the original number:
Multiplying aα + bβ by the ideal number ι gives 2a + by, which is the nonprincipal ideal.
Multiplying the number of sprocket gears in front by the number to the rear gives the number of gear ratios, often called " speeds ".
Multiplying the number 1089 by the integers from 1 to 9 produces a pattern: multipliers adding up to 10 give products that are the digit reversals of each other.
Multiplying K degree-days per gallon by the number of gallon of usable fuel remaining in a tank gives the number of degree-days before a delivery is needed.
Multiplying the numerator and denominator of a fraction by the same ( non-zero ) number results in a fraction that is equivalent to the original fraction.

Multiplying and by
Multiplying both sides by, we get
Multiplying by a linear phase for some integer m corresponds to a circular shift of the output: is replaced by, where the subscript is interpreted modulo N ( i. e., periodically ).
Multiplying the impulse response shifted in time according to the arrival of each of these delta functions by the amplitude of each delta function, and summing these responses together ( according to the superposition principle, applicable to all linear systems ) yields the output waveform.
Multiplying the top and bottom of the righthand side by and rewriting, we obtain:
Multiplying both sides of this equation by ( x < sub > 2 </ sub > − x < sub > 1 </ sub >) yields a form of the line generally referred to as the symmetric form:
Multiplying mole fraction by 100 gives the mole percentage, also referred as amount / amount percent ( abbreviated as n / n %).
Multiplying the Dirac equation by from the left, and the adjoint equation by from the right, and subtracting, produces the law of conservation of the Dirac current:
Multiplying the temperature change by the mass and specific heat capacities of the substances gives a value for the energy given off or absorbed during the reaction.
Multiplying the energy equation by Ψ
Multiplying these by gives
Multiplying by the molar mass constant ensures that the calculation is dimensionally correct: atomic weights are dimensionless quantities ( i. e., pure numbers ) whereas molar masses have units ( in this case, grams / mole ).
Multiplying by a power of 256 adds as many trailing null characters to the gzip file as indicated in the exponent which would still result in the DeCSS C code when unzipped.
Multiplying an n-by-n matrix A from the left with diag ( a < sub > 1 </ sub >,..., a < sub > n </ sub >) amounts to multiplying the i-th row of A by a < sub > i </ sub > for all i ; multiplying the matrix A from the right with diag ( a < sub > 1 </ sub >,..., a < sub > n </ sub >) amounts to multiplying the i-th column of A by a < sub > i </ sub > for all i.
Multiplying C < sub > d </ sub > by the car's frontal area gives an index of total drag.
Multiplying the equation by gives us the future value.
It has a dihedral D < sub > 4 </ sub > subgroup ( in fact it has three such ) of order 8, and thus of index 3 in O, which we shall call H. This dihedral group has a 4-member D < sub > 2 </ sub > subgroup, which we may call A. Multiplying on the right any element of a right coset of H by an element of A gives a member of the same coset of H ( Hca = Hc ).
Multiplying a row vector h times will permute the columns of the vector by the inverse of:
* Multiplying by 1 does not change a vector: 1v =
* Multiplying by 0 gives the null vector: 0v = 0 ;
Multiplying through by x < sup > 2 </ sup > + 2x-3, we have the polynomial identity

Multiplying and then
Multiplying the bottom equation by and then subtracting from the top equation one obtains

Multiplying and adding
Multiplying the numbers is the same as componentwise adding their exponent vectors: ( 504 )( 490 ) has the vector ( 4, 2, 1, 3 ).
Multiplying, and by and respectively and adding all three yields
Multiplying or adding two integers may result in a value that is non-negative, but unexpectedly small.

Multiplying and 1
* Multiplying by-1 gives the additive inverse: (- 1 ) v =-v.
Multiplying through by ( x − 1 )< sup > 3 </ sup >( x < sup > 2 </ sup > + 1 )< sup > 2 </ sup > we have the polynomial identity
Multiplying the left hand side by, which is approximately equal to 1, we obtain
Multiplying both sides of the equation 4 / n = 1 / x + 1 / y + 1 / z by nxyz leads to an equivalent form 4xyz = n ( xy + xz + yz ) for the problem.

Multiplying and yields
Multiplying out yields the elementary symmetric functions of the:
Multiplying the AM signal x ( t ) by an oscillator at the same frequency as and in phase with the carrier yields
Multiplying the AM signal by the new set of frequencies yields
Multiplying by and integrating both sides yields

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